Find the distance between the pairs of points:  (2, 3, 5) and (4, 3, 1)

Asked by Abhisek | 11 months ago |  52

Solution :-

(2, 3, 5) and (4, 3, 1)

Let P be (2, 3, 5) and Q be (4, 3, 1)

By using the formula,

Distance PQ = [(x2 – x1)2 + (y2 – y1)2 + (z2 – z1)2]

So here,

x1 = 2, y1 = 3, z1 = 5

x2 = 4, y2 = 3, z2 = 1

Distance PQ =

$$\sqrt{(4 – 2)^2 + (3 – 3)^2 + (1 – 5)^2}$$

$$\sqrt{(2)^2 + 0^2 + (-4)^2}$$

$$\sqrt{4 + 0 + 16}$$

$$\sqrt{20}$$

$$2 \sqrt{5}$$

The required distance is $$2 \sqrt{5}$$ units.

Answered by Pragya Singh | 11 months ago

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