Find the distance between the pairs of points:(–1, 3, – 4) and (1, –3, 4)

Asked by Abhisek | 11 months ago |  114

1 Answer

Solution :-

(–1, 3, – 4) and (1, –3, 4)

Let P be (– 1, 3, – 4) and Q be (1, – 3, 4)

So here,

x1 = – 1, y1 = 3, z1 = – 4

x2 = 1, y2 = – 3, z2 = 4

Distance PQ = 

\( \sqrt{(1 – (-1))^2 + (-3 – 3)^2 + (4 – (-4))^2}\)

\( \sqrt{(2)^2 + (-6)?^2 + (8)^2}\)

\( \sqrt{4 + 36 + 64}\)

= \( \sqrt{104}\)

= \( 2\sqrt{26}\)

The required distance is \( 2\sqrt{26}\) units.

Answered by Pragya Singh | 11 months ago

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