Find the distance between the pairs of points: (2, –1, 3) and (–2, 1, 3)

Asked by Abhisek | 11 months ago |  126

1 Answer

Solution :-

Let P be (2, – 1, 3) and Q be (– 2, 1, 3)

So here,

x1 = 2, y1 = – 1, z1 = 3

x2 = – 2, y2 = 1, z2 = 3

Distance PQ = 

\( \sqrt{(-2 – 2)^2 + (1 – (-1))^2 + (3 – 3)^2}\)

\( \sqrt{(-4)^2 + (2)^2 + (0)^2}\)

\( \sqrt{16 + 4 + 0}\)

\( \sqrt{20}\)

\( 2\sqrt{5}\)

The required distance is \( 2\sqrt{5}\) units.

Answered by Pragya Singh | 11 months ago

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