Let P be (2, – 1, 3) and Q be (– 2, 1, 3)
So here,
x1 = 2, y1 = – 1, z1 = 3
x2 = – 2, y2 = 1, z2 = 3
Distance PQ =
\( \sqrt{(-2 – 2)^2 + (1 – (-1))^2 + (3 – 3)^2}\)
= \( \sqrt{(-4)^2 + (2)^2 + (0)^2}\)
= \( \sqrt{16 + 4 + 0}\)
= \( \sqrt{20}\)
= \( 2\sqrt{5}\)
The required distance is \( 2\sqrt{5}\) units.
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