Let P be (2, – 1, 3) and Q be (– 2, 1, 3)

So here,

x_{1} = 2, y_{1} = – 1, z_{1} = 3

x_{2} = – 2, y_{2} = 1, z_{2} = 3

Distance PQ =

\( \sqrt{(-2 – 2)^2 + (1 – (-1))^2 + (3 – 3)^2}\)

= \( \sqrt{(-4)^2 + (2)^2 + (0)^2}\)

= \( \sqrt{16 + 4 + 0}\)

**= \( \sqrt{20}\)**

= \( 2\sqrt{5}\)

The required distance is \( 2\sqrt{5}\) units.

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