Let the ratio in which the point Q divides the line segment joining the
points P(3,2,-4) and R(9,8,-10) be k:1.
Using section formula,
\((5,4,-6)= (\dfrac{k(9)+3}{k+1}, \dfrac{k(8)+2}{k+1}, \)
\( \dfrac{k(-10)-4}{k+1} )\)
= \( \dfrac{9k+3}{k+1}=5\)
= 9k+3 = 5k+5
= 4k = 2
= \( k=\dfrac{2}{4}\)
k = \( \dfrac{1}{2}\)
Therefore, the ratio in which the point Q divides the line segment joining the points P(3,2,-4) and R(9,8,-10) is 1:2.
Answered by Pragya Singh | 1 year agoA(1, 2, 3), B(0, 4, 1), C(-1, -1, -3) are the vertices of a triangle ABC. Find the point in which the bisector of the angle ∠BAC meets BC.
The mid-points of the sides of a triangle ABC are given by (-2, 3, 5), (4, -1, 7) and (6, 5, 3). Find the coordinates of A, B and C.
If the points A(3, 2, -4), B(9, 8, -10) and C(5, 4, -6) are collinear, find the ratio in which C divided AB.
Find the ratio in which the line segment joining the points (2, -1, 3) and (-1, 2, 1) is divided by the plane x + y + z = 5.
Find the ratio in which the line joining (2, 4, 5) and (3, 5, 4) is divided by the yz-plane.