The equation of the given circle is x2 + y2 -8x + 10y -12 = 0.
x2 + y2 – 8x + 10y – 12 = 0
(x2 – 8x) + (y2 + 10y) = 12
(x2 – 2(x) (4) + 42) + (y2 – 2(y) (5) + 52) – 16 – 25 = 12
(x – 4)2 + (y + 5)2 = 53
(x – 4)2 + (y – (-5))2 = \( ( \sqrt{53})^2\) [which is form (x-h)2 +(y-k)2 = r2]
Where h = 4, K= -5 and r = \( \sqrt{53}\)
The centre of the given circle is (4, -5) and its radius is \( \sqrt{53}\).
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