Find the centre and radius of the circle 2x2 + 2y2 – x = 0

Asked by Abhisek | 1 year ago |  155

##### Solution :-

The equation of the given of the circle is 2x2 + 2y2 –x = 0.

2x2 + 2y2 –x = 0

(2x2 + x) + 2y2 = 0

(x2 – 2 (x) ($$\dfrac{1}{4}$$) + ($$\dfrac{1}{4}$$)2) + y2 – ($$\dfrac{1}{4}$$)2 = 0

(x –$$\dfrac{1}{4}$$)2 + (y – 0)2 = ($$\dfrac{1}{4}$$)2 [which is form (x-h)2 +(y-k)2 = r2]

Where, h = $$\dfrac{1}{4}$$, K = 0, and r =$$\dfrac{1}{4}$$

The center of the given circle is ($$\dfrac{1}{4}$$, 0) and its radius is $$\dfrac{1}{4}$$.

Answered by Pragya Singh | 1 year ago

### Related Questions

#### An equilateral triangle is inscribed in the parabola y2 = 4ax,

An equilateral triangle is inscribed in the parabola y2 = 4ax, where one vertex is at the vertex of the parabola. Find the length of the side of the triangle.

#### A man running a racecourse notes that the sum of the distances from the two flag posts from him is always

A man running a racecourse notes that the sum of the distances from the two flag posts from him is always 10 m and the distance between the flag posts is 8 m. Find the equation of the posts traced by the man.

#### Find the area of the triangle formed by the lines joining the vertex of the parabola x2 = 12y to the ends

Find the area of the triangle formed by the lines joining the vertex of the parabola x2 = 12y to the ends of its latus rectum.