Does the point (–2.5, 3.5) lie inside, outside or on the circle x2 + y2 = 25?

Asked by Abhisek | 1 year ago |  109

##### Solution :-

Given:

The equation of the given circle is x2 +y2 = 25.

x2 + y2 = 25

(x – 0)2 + (y – 0)2 = 52

[which is of the form (x – h)+ (y – k)2 = r2]

Where, h = 0, k = 0 and r = 5.

So the distance between point (-2.5, 3.5) and the centre (0,0) is

$$\sqrt{(-2.5 – 0)^2 + (-3.5 – 0)^2}$$

$$\sqrt{(6.25 + 12.25}$$

$$\sqrt{18.5}$$

= 4.3 [which is < 5]

Since, the distance between point (-2.5, -3.5) and the centre (0, 0) of the circle is less than the radius of the circle, point (-2.5, -3.5) lies inside the circle.

Answered by Pragya Singh | 1 year ago

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