The equation is y2 = 10x
Here we know that the coefficient of x is positive.
So, the parabola open towards the right.
On comparing this equation with y2 = 4ax, we get,
4a = 10
a = \( \dfrac{10}{4}\) = \( \dfrac{5}{2}\)
Thus, co-ordinates of the focus = (a,0) = (\( \dfrac{5}{2}\), 0)
Since, the given equation involves y2, the axis of the parabola is the x-axis.
The equation of directrix, x = -a, then,
x = \( - \dfrac{5}{2}\)
Length of latus rectum = 4a = 4(\( \dfrac{5}{2}\)) = 10
Answered by Abhisek | 1 year agoAn equilateral triangle is inscribed in the parabola y2 = 4ax, where one vertex is at the vertex of the parabola. Find the length of the side of the triangle.
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