Find the equation of the parabola that satisfies the given conditions: Focus (6,0); directrix x = – 6

Asked by Pragya Singh | 1 year ago |  124

1 Answer

Solution :-

Focus (6,0) and directrix x = -6

We know that the focus lies on the x–axis is the axis of the parabola.

So, the equation of the parabola is either of the form y2 = 4ax or y2 = -4ax.

It is also seen that the directrix, x = -6 is to the left of the y- axis,

While the focus (6, 0) is to the right of the y –axis.

Hence, the parabola is of the form y2 = 4ax.

Here, a = 6

The equation of the parabola is y2 = 24x.

Answered by Abhisek | 1 year ago

Related Questions

An equilateral triangle is inscribed in the parabola y2 = 4ax, where one vertex is at the vertex of the parabola. Find the length of the side of the triangle.

Class 11 Maths Conic Sections View Answer

A man running a racecourse notes that the sum of the distances from the two flag posts from him is always 10 m and the distance between the flag posts is 8 m. Find the equation of the posts traced by the man.

Class 11 Maths Conic Sections View Answer

Find the area of the triangle formed by the lines joining the vertex of the parabola x2 = 12y to the ends of its latus rectum.

Class 11 Maths Conic Sections View Answer

A rod of length 12 cm moves with its ends always touching the coordinate axes. Determine the equation of the locus of a point P on the rod, which is 3 cm from the end in contact with the x-axis.

Class 11 Maths Conic Sections View Answer

An arch is in the form of a semi-ellipse. It is 8 m wide and 2 m high at the centre. Find the height of the arch at a point 1.5 m from one end.

Class 11 Maths Conic Sections View Answer