We know that the vertex is (0, 0) and the axis of the parabola is the x-axis

The equation of the parabola is either of the from y^{2 }= 4ax or y^{2} = -4ax.

Given that the parabola passes through point (2, 3), which lies in the first quadrant.

So, the equation of the parabola is of the form

y^{2} = 4ax, while point (2, 3) must satisfy the equation y^{2} = 4ax.

Then,

3^{2} = 4a(2)

3^{2} = 8a

9 = 8a

a = \( \dfrac{9}{8}\)

Thus, the equation of the parabola is

y^{2} = 4\( (\dfrac{9}{8})x\)

y^{2 }= \( \dfrac{9}{8}x\)

2y^{2} = 9x

The equation of the parabola is 2y^{2} = 9x

An equilateral triangle is inscribed in the parabola y^{2} = 4ax, where one vertex is at the vertex of the parabola. Find the length of the side of the triangle.

A man running a racecourse notes that the sum of the distances from the two flag posts from him is always 10 m and the distance between the flag posts is 8 m. Find the equation of the posts traced by the man.

Find the area of the triangle formed by the lines joining the vertex of the parabola x^{2} = 12y to the ends of its latus rectum.

A rod of length 12 cm moves with its ends always touching the coordinate axes. Determine the equation of the locus of a point P on the rod, which is 3 cm from the end in contact with the x-axis.

An arch is in the form of a semi-ellipse. It is 8 m wide and 2 m high at the centre. Find the height of the arch at a point 1.5 m from one end.