b = 3, c = 4, centre at the origin and foci on the x axis.

Since the foci are on the x-axis, the major axis is along the x-axis.

So, the equation of the ellipse will be of the form

\( \dfrac{x^2}{a^2}\) +\( \dfrac{y^2}{b^2}\) = 1, where ‘a’ is the semi-major axis.

Then, b = 3 and c = 4.

It is known that a^{2} = b^{2 }+ c^{2}.

a^{2} = 3^{2 }+ 4^{2}

= 9 + 16

=25

a =\( \sqrt{25}\)

= 5

The equation of the ellipse is \( \dfrac{x^2}{5^2}+ \dfrac{y^2}{3^2}=1\)

or \( \dfrac{x^2}{25}+ \dfrac{y^2}{9}=1\)

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