We know that the origin of the coordinate plane is taken at the vertex of the parabolic reflector, where the axis of the reflector is along the positive x – axis.
Diagrammatic representation is as follows
We know that the equation of the parabola is of the form y2 = 4ax (as it is opening to the right)
Since, the parabola passes through point A(10, 5),
y2 = 4ax
102 = 4a(5)
100 = 20a
a = \( \dfrac{100}{20}\)
= 5
The focus of the parabola is (a, 0) = (5, 0), which is the mid – point of the diameter.
Hence, the focus of the reflector is at the mid-point of the diameter.
Answered by Abhisek | 1 year agoAn equilateral triangle is inscribed in the parabola y2 = 4ax, where one vertex is at the vertex of the parabola. Find the length of the side of the triangle.
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