Consider the given population and year graph. Find the slope of the line AB and using it

We know that, the line AB passes through points A (1985, 92) and B (1995, 97),

Its slope will be \( \dfrac{(97 – 92)}{(1995 – 1985)} \)

= \( \dfrac{5}{10} \) = \( \dfrac{1}{2} \)

Let ‘y’ be the population in the year 2010. Then, according to the given graph, AB must pass through point C (2010, y)

So now, slope of AB = slope of BC

\( \dfrac{1}{2} =\dfrac{y-97}{2010-1995}\)

\( \dfrac{15}{2} \) = y – 97

y = 7.5 + 97 = 104.5

The slope of the line AB is \( \dfrac{1}{2} \), while in the year 2010 the population will be 104.5 crores.