Given: θ = 30°

We know that slope, m = tan θ

m = tan30° = (\( \dfrac{1}{\sqrt{3}}\))

We know that the point (x, y) on the line with slope m and y-intercept c lies on the line if and only if y = mx + c.

If distance is 2 units above the origin, c = +2

So, y = \( \dfrac{1}{\sqrt{3}}x\) + 2

y = \( \dfrac{x+2\sqrt{3}}{\sqrt{3}}\)

\( \sqrt{3}y= x +\) \(2 \sqrt{3}\)

\( x- \sqrt{3}y+ 2 \sqrt{3}=0\) \(\)

The equation of the line is

\( x- \sqrt{3}y+ 2 \sqrt{3}=0\)

Answered by Abhisek | 11 months ago

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