Find the equation of the line which satisfy the given conditions passing through the points (–1, 1) and (2, – 4).

Asked by Pragya Singh | 11 months ago |  83

##### Solution :-

Points (-1, 1) and (2, -4)

We know that the equation of the line passing through the points (x1, y1) and (x2, y2) is given by

$$y-1=\dfrac{-4-1}{2-(-1)}(x-(-1))$$

y – 1 = $$\dfrac{-5}{3}$$ (x + 1)

3 (y – 1) = (-5) (x + 1)

3y – 3 = -5x – 5

3y – 3 + 5x + 5 = 0

5x + 3y + 2 = 0

The equation of the line is 5x + 3y + 2 = 0.

Answered by Abhisek | 11 months ago

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