(i) x + 7y = 0
Given:
The equation is x + 7y = 0
Slope – intercept form is represented in the form ‘y = mx + c’, where m is the slope and c is the y intercept
So, the above equation can be expressed as
y = \(- \dfrac{1}{7}x\) + 0
The above equation is of the form y = mx + c, where m = \( \dfrac{1}{7}\) and c = 0.
(ii) 6x + 3y – 5 = 0
Given:
The equation is 6x + 3y – 5 = 0
Slope – intercept form is represented in the form ‘y = mx + c’, where m is the slope and c is the y intercept
So, the above equation can be expressed as
3y = -6x + 5
y = \(- \dfrac{6}{3}x\) + \( \dfrac{5}{3}\)
= -2x +\( \dfrac{5}{3}\)
The above equation is of the form y = mx + c, where m = -2 and c = \( \dfrac{5}{3}\).
(iii) y = 0
Given:
The equation is y = 0
Slope – intercept form is given by ‘y = mx + c’, where m is the slope and c is the y intercept
y = 0 × x + 0
The above equation is of the form y = mx + c, where m = 0 and c = 0.
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