Find equation of the line parallel to the line 3x − 4y + 2 = 0 and passing through the point (–2, 3).

Asked by Pragya Singh | 1 year ago |  96

##### Solution :-

The line is 3x – 4y + 2 = 0

So, y = $$\dfrac{3}{4}x$$ +$$\dfrac{2}{4}$$

$$\dfrac{3}{4}x$$$$\dfrac{1}{2}$$

Which is of the form y = mx + c, where m is the slope of the given line.

The slope of the given line is $$\dfrac{3}{4}$$

We know that parallel line have same slope.

Slope of other line = m = $$\dfrac{3}{4}$$

Equation of line having slope m and passing through (x1, y1) is given by

y – y1 = m (x – x1)

Equation of line having slope $$\dfrac{3}{4}$$ and passing through (-2, 3) is

y – 3 = $$\dfrac{3}{4}$$ (x – (-2))

4y – 3 × 4 = 3x + 3 × 2

3x – 4y = 18

The equation is 3x – 4y = 18

Answered by Abhisek | 1 year ago

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