1 Answer
Solution :-
The lines are \( \sqrt{3}x + y = 1\) and \( x + \sqrt{3}y = 1\)
So, y = \( -\sqrt{3}x + 1\) … (1) and
y = \(-\dfrac{1}{\sqrt{3}}+\dfrac{1}{\sqrt{3}}\)…. (2)
Slope of line (1) is m1 =\( -\sqrt{3}\) , while the slope of line (2) is m2 = \( -\dfrac{1}{\sqrt{3}}\)
Let θ be the angle between two lines
Substitute the values, tan θ
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θ = 30°
The angle between the given lines is either 30° or 180°- 30° = 150°
Answered by Abhisek | 1 year agoRelated Questions
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