The lines are \( \sqrt{3}x + y = 1\) and \( x + \sqrt{3}y = 1\)

So, y = \( -\sqrt{3}x + 1\) … (1) and

y = \(-\dfrac{1}{\sqrt{3}}+\dfrac{1}{\sqrt{3}}\)…. (2)

Slope of line (1) is m_{1} =\( -\sqrt{3}\) , while the slope of line (2) is m_{2} = \( -\dfrac{1}{\sqrt{3}}\)

Let θ be the angle between two lines

Substitute the values, tan θ

θ = 30°

The angle between the given lines is either 30° or 180°- 30° = 150°

Answered by Abhisek | 1 year agoFind the angle between the line joining the points (2, 0), (0, 3) and the line x + y = 1.

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