Find angles between the lines $$\sqrt{3}x + y = 1$$ and  $$x+ \sqrt{3}y$$ = 1.

Asked by Pragya Singh | 1 year ago |  145

##### Solution :-

The lines are $$\sqrt{3}x + y = 1$$ and $$x + \sqrt{3}y = 1$$

So, y = $$-\sqrt{3}x + 1$$ … (1) and

y = $$-\dfrac{1}{\sqrt{3}}+\dfrac{1}{\sqrt{3}}$$…. (2)

Slope of line (1) is m1 =$$-\sqrt{3}$$ , while the slope of line (2) is m2 = $$-\dfrac{1}{\sqrt{3}}$$

Let θ be the angle between two lines

Substitute the values, tan θ

θ = 30°

The angle between the given lines is either 30° or 180°- 30° = 150°

Answered by Abhisek | 1 year ago

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