The perpendicular from the origin meets the given line at (–1, 2).

The equation of line is y = mx + c

The line joining the points (0, 0) and (–1, 2) is perpendicular to the given line.

So, the slope of the line joining (0, 0) and (–1, 2)

= \(- \dfrac{2}{1}\) = -2

Slope of the given line is m.

m × (-2) = -1

m = \( \dfrac{1}{2}\)

Since, point (-1, 2) lies on the given line,

y = mx + c

2 = \( \dfrac{1}{2}\) × (-1) + c

c = 2 + \( \dfrac{1}{2}\) = \( \dfrac{5}{2}\)

The values of m and c are \( \dfrac{1}{2}\) and \( \dfrac{5}{2}\) respectively.

Answered by Pragya Singh | 1 year agoFind the angle between the line joining the points (2, 0), (0, 3) and the line x + y = 1.

Prove that the points (2, -1), (0, 2), (2, 3) and (4, 0) are the coordinates of the vertices of a parallelogram and find the angle between its diagonals.

Find the acute angle between the lines 2x – y + 3 = 0 and x + y + 2 = 0.

Find the angles between pairs of straight lines 3x – y + 5 = 0 and x – 3y + 1 = 0

Find the angles between pairs of straight lines 3x + y + 12 = 0 and x + 2y – 1 = 0