The perpendicular from the origin to the line y = mx + c meets it at the point (–1, 2). Find the values of m and c.

Asked by Abhisek | 1 year ago |  148

##### Solution :-

The perpendicular from the origin meets the given line at (–1, 2).

The equation of line is y = mx + c

The line joining the points (0, 0) and (–1, 2) is perpendicular to the given line.

So, the slope of the line joining (0, 0) and (–1, 2)

$$- \dfrac{2}{1}$$ = -2

Slope of the given line is m.

m × (-2) = -1

m = $$\dfrac{1}{2}$$

Since, point (-1, 2) lies on the given line,

y = mx + c

2 = $$\dfrac{1}{2}$$ × (-1) + c

c = 2 + $$\dfrac{1}{2}$$$$\dfrac{5}{2}$$

The values of m and c are $$\dfrac{1}{2}$$ and $$\dfrac{5}{2}$$ respectively.

Answered by Pragya Singh | 1 year ago

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