Find the equation of the line parallel to y-axis and drawn through the point of intersection of the lines x – 7y + 5 = 0 and 3x + y = 0.

Asked by Abhisek | 1 year ago |  90

##### Solution :-

Here the equation of any line parallel to the y-axis is of the form

x = a ……. (1)

Two given lines are

x – 7y + 5 = 0 …… (2)

3x + y = 0 …… (3)

By solving equations (2) and (3) we get

x = $$- \dfrac{5}{22}$$ and y = $$\dfrac{15}{22}$$

($$- \dfrac{5}{22}$$,$$\dfrac{15}{22}$$) is the point of intersection of lines (2) and (3)

If the line x = a passes through point ($$- \dfrac{5}{22}$$, $$\dfrac{15}{22}$$) we get a = $$- \dfrac{5}{22}$$

Hence, the required equation of the line is x = $$- \dfrac{5}{22}$$.

Answered by Pragya Singh | 1 year ago

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