Find the value of p so that the three lines 3x + y – 2 = 0, px + 2y – 3 = 0 and 2x – y – 3 = 0 may intersect at one point.

Asked by Abhisek | 1 year ago |  102

##### Solution :-

It is given that

3x + y – 2 = 0 …… (1)

px + 2y – 3 = 0 ….. (2)

2x – y – 3 = 0 …… (3)

By solving equations (1) and (3) we get

x = 1 and y = -1

Here the three lines intersect at one point and the point of intersection of lines (1) and (3) will also satisfy line (2)

p (1) + 2 (-1) – 3 = 0

By further calculation

p – 2 – 3 = 0

So we get

p = 5

Hence, the required value of p is 5.

Answered by Pragya Singh | 1 year ago

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