Given nth term, an = (-1)n-1 5n+1
On substituting n = 1, 2, 3, 4, 5, we get
\( a_1=(-1)^{1-1}5^{1+1}\)
\( a_1=5^2-25\)
\( a_2=(-1)^{2-1}5^{2+1}\)
\( a_2=-5^3=-125\)
\( a_3=(-1)^{3-1}5^{3+1}\)
\( a_3=5^4=625\)
\( a_4=(-1)^{4-1}5^{4+1}\)
\( a_4=-5^5=-3125\)
\( a_5=(-1)^{5-1}5^{5+1}\)
\( a_5=5^6=15625\)
Hence, the required terms are 25, –125, 625, –3125, and 15625.
Answered by Abhisek | 1 year agoConstruct a quadratic in x such that A.M. of its roots is A and G.M. is G.
Find the geometric means of the following pairs of numbers:
(i) 2 and 8
(ii) a3b and ab3
(iii) –8 and –2
Insert 5 geometric means between \( \dfrac{32}{9}\) and \( \dfrac{81}{2}\).