Find the 7th term in the following sequence whose an = $$\dfrac{n^2}{2^n}$$; a7

Asked by Abhisek | 1 year ago |  75

##### Solution :-

nth term of the sequence is an = $$\dfrac{n^2}{2^n}$$

Now, on substituting n = 7, we get

a7 = $$\dfrac{7^2}{2^7}$$

$$\dfrac{49}{128}$$

Answered by Pragya Singh | 1 year ago

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