Find the 7th term in the following sequence whose an = \( \dfrac{n^2}{2^n}\); a7

Asked by Abhisek | 1 year ago |  75

1 Answer

Solution :-

nth term of the sequence is an = \( \dfrac{n^2}{2^n}\)

Now, on substituting n = 7, we get

a7 = \( \dfrac{7^2}{2^7}\)

\( \dfrac{49}{128}\)

Answered by Pragya Singh | 1 year ago

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