Find the 20th term in the following sequence whose nth term $$a_n=\dfrac{n(n-2)}{(n+3)}$$

Asked by Abhisek | 1 year ago |  86

Solution :-

The given equation is $$a_n=\dfrac{n(n-2)}{(n+3)}$$

On substituting n = 20, we get

$$a_{20}=\dfrac{20(20-2)}{(20+3)}$$

$$a_{20}=\dfrac{360}{23}$$

Therefore, the 20th term of

$$a_n=\dfrac{n(n-2)}{(n+3)}$$ is $$\dfrac{360}{23}$$

Answered by Pragya Singh | 1 year ago

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