Find the 20th term in the following sequence whose nth term \( a_n=\dfrac{n(n-2)}{(n+3)}\)

Asked by Abhisek | 1 year ago |  86

1 Answer

Solution :-

The given equation is \( a_n=\dfrac{n(n-2)}{(n+3)}\)

On substituting n = 20, we get

\( a_{20}=\dfrac{20(20-2)}{(20+3)}\)

\( a_{20}=\dfrac{360}{23}\)

Therefore, the 20th term of 

\( a_n=\dfrac{n(n-2)}{(n+3)}\) is \( \dfrac{360}{23}\)

Answered by Pragya Singh | 1 year ago

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