1 = a1 = a2
an = an – 1 + an – 2, n > 2
So,
a3 = a2 + a1 = 1 + 1 = 2
a4 = a3 + a2 = 2 + 1 = 3
a5 = a4 + a3 = 3 + 2 = 5
a6 = a5 + a4 = 5 + 3 = 8
Substitute the values of 1 a and 2 a in the expression \( \dfrac{a_n+1}{a_n}\) for n=1
for n = 1, \( \dfrac{a_{1+1}}{a_1}= \dfrac{1}{1}=1\)
For n= 2, \( \dfrac{a_{2+1}}{a_2}= \dfrac{2}{1}=2\)
For n= 3, \( \dfrac{a_{3+1}}{a_3}= \dfrac{3}{2}\)
For n= 4, \( \dfrac{a_{4+1}}{a_4}= \dfrac{5}{3}\)
For n= 5, \( \dfrac{a_{5+1}}{a_5}= \dfrac{8}{5}\)
Answered by Pragya Singh | 1 year agoConstruct a quadratic in x such that A.M. of its roots is A and G.M. is G.
Find the geometric means of the following pairs of numbers:
(i) 2 and 8
(ii) a3b and ab3
(iii) –8 and –2
Insert 5 geometric means between \( \dfrac{32}{9}\) and \( \dfrac{81}{2}\).