The first term (a) of an A.P = 2
Let’s assume d be the common difference of the A.P.
So, the A.P. will be 2, 2 + d, 2 + 2d, 2 + 3d, …
Then,
Sum of first five terms = 10 + 10d
Sum of next five terms = 10 + 35d
From the question, we have
10 + 10d = \( \dfrac{1}{4}\)(10 + 35d)
40 + 40d = 10 + 35d
30 = -5d
d = -6
a20 = a + (20 – 1)d = 2 + (19) (-6) = 2 – 114 = -112
Therefore, the 20th term of the A.P. is –112.
Answered by Abhisek | 1 year agoConstruct a quadratic in x such that A.M. of its roots is A and G.M. is G.
Find the geometric means of the following pairs of numbers:
(i) 2 and 8
(ii) a3b and ab3
(iii) –8 and –2
Insert 5 geometric means between \( \dfrac{32}{9}\) and \( \dfrac{81}{2}\).