It’s understood from the question that, the angles of the polygon will form an A.P. with common difference d = 5° and first term a = 120°.
And, we know that the sum of all angles of a polygon with n sides is 180° (n – 2).
Thus, we can say
sn = 180° (n – 2)
\( s_n=\dfrac{n}{2}[2a+(n-1)d]\)
= 180° (n – 2)
\(=\dfrac{n}{2}[240°+(n-1)5°]\)
= 180° (n – 2)
= n[240+5n−5]=360(n−2)
= 240n+5n2−5n=360n−720
= 5n2−125n+720=0
= n2−25n+144=0
= (n−9)(n−16)=0
n = 9,16
Therefore, the number of the sides of the polygon 9 or 16 .
Answered by Pragya Singh | 1 year agoConstruct a quadratic in x such that A.M. of its roots is A and G.M. is G.
Find the geometric means of the following pairs of numbers:
(i) 2 and 8
(ii) a3b and ab3
(iii) –8 and –2
Insert 5 geometric means between \( \dfrac{32}{9}\) and \( \dfrac{81}{2}\).