Find the sum to n terms in the geometric progression \( \sqrt{7}\), \( \sqrt{21}\), \(3 \sqrt{7}\), …

Asked by Abhisek | 1 year ago |  101

1 Answer

Solution :-

The given G.P is \( \sqrt{7}\), \( \sqrt{21}\), \(3 \sqrt{7}\), ….

Here,

a = \( \sqrt{7}\) and

r= \( \dfrac{\sqrt{21}}{\sqrt{7}}=\sqrt{3} \)

\( s_n=\dfrac{a(1-r^n)}{1-r}\)

\( \dfrac{\sqrt{7[1-(\sqrt{3})^n}]}{1-\sqrt{3}}\)

By rationalizing

\( \dfrac{\sqrt{7[1-(\sqrt{3})^n}]}{1-\sqrt{3}}\times\dfrac{1+\sqrt{3}}{1+\sqrt{3}}\)

\(\dfrac{\sqrt{7}(1+\sqrt{3})(1-\sqrt{3})^n)}{1-3}\)

\( \dfrac{\sqrt{7}(1+\sqrt{3})}{2}[(3)^\dfrac{n}{2}-1]\)

Answered by Pragya Singh | 1 year ago

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