Given, the farmer pays Rs 6000 in cash.
So, the unpaid amount = Rs 12000 – Rs 6000 = Rs 6000
From the question, the interest paid annually will be
12% of 6000, 12% of 5500, 12% of 5000, …, 12% of 500
Hence, the total interest to be paid = 12% of 6000 + 12% of 5500 + 12% of 5000 + … + 12% of 500
= 12% of (6000 + 5500 + 5000 + … + 500)
= 12% of (500 + 1000 + 1500 + … + 6000)
It’s seen that, the series 500, 1000, 1500 … 6000 is an A.P. with the first term and common difference both equal to 500.
Let’s take the number of terms of the A.P. to be n.
So, 6000 = 500 + (n – 1) 500
1 + (n – 1) = 12
n = 12
Now,
The sum of the A.P = 12/2 [2(500) + (12 – 1)(500)] = 6 [1000 + 5500] = 6(6500) = 39000
Hence, the total interest to be paid = 12% of (500 + 1000 + 1500 + … + 6000)
= 12% of 39000 = Rs 4680
Therefore, the tractor will cost the farmer = (Rs 12000 + Rs 4680) = Rs 16680
Answered by Abhisek | 1 year agoConstruct a quadratic in x such that A.M. of its roots is A and G.M. is G.
Find the geometric means of the following pairs of numbers:
(i) 2 and 8
(ii) a3b and ab3
(iii) –8 and –2
Insert 5 geometric means between \( \dfrac{32}{9}\) and \( \dfrac{81}{2}\).