Solve – 12x > 30, when

(i) x is a natural number.

(ii) x is an integer.

Asked by Abhisek | 1 year ago |  117

##### Solution :-

(i) Given that, – 12x > 30

Now by dividing the inequality by -12 on both sides we get, x < $$- \dfrac{5}{2}$$

When x is a natural integer then

It is clear that there is no natural number less than $$- \dfrac{2}{5}$$ because $$- \dfrac{5}{2}$$ is a negative number and natural numbers are positive numbers.

Therefore there would be no solution of the given inequality when x is a natural number.

(ii) Given that, – 12x > 30

Now by dividing the inequality by -12 on both sides we get, x < $$- \dfrac{5}{2}$$

When x is an integer then

It is clear that the integer number less than $$- \dfrac{5}{2}$$ are…, -5, -4, – 3

Thus, solution of – 12x > 30 is …,-5, -4, -3, when x is an integer.

Therefore the solution set is {…, -5, -4, -3}

Answered by Pragya Singh | 1 year ago

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