= \( \dfrac{x}{3}\) > \( \dfrac{x}{2}\)+ 1
= \( \dfrac{x}{3}- \dfrac{x}{2}>1\)
= \( \dfrac{2x-3x}{6}>1\)
= \( - \dfrac{x}{6}>1\)
= \(-x>6\)
= x < -6
Thus, all real numbers x, which are less than -6, are the solutions of the given inequality.
Hence, the solution set of the given inequality is (-∞, -6)
Answered by Pragya Singh | 1 year agoSolve each of the following in equations and represent the solution set on the number line \( \dfrac{5x}{4}-\dfrac{4x-1}{3}>1,\) where x ϵ R.
Solve each of the following in equations and represent the solution set on the number line.\( \dfrac{5x-8}{3}\geq \dfrac{4x-7}{2}\), where x ϵ R.
Solve each of the following in equations and represent the solution set on the number line. 3 – 2x ≥ 4x – 9, where x ϵ R.
Solve each of the following in equations and represent the solution set on the number line. 3x – 4 > x + 6, where x ϵ R.
Solve each of the following in equations and represent the solution set on the number line. 5x + 2 < 17, where
(i) x ϵ Z,
(ii) x ϵ R.