\( \dfrac{1}{2}(\dfrac{3x}{5}+4)≥\dfrac{1}{3}(x-6)\)
\(3(\dfrac{3x}{5}+4)≥2(x-6)\)
\( \dfrac{9x}{5}+12≥2x-12\)
\(12+12≥2x- \dfrac{9x}{5}\)
\(24≥\dfrac{10x-9x}{5}\)
\( 24≥\dfrac{x}{5}\)
\( 120≥x\)
Thus, all real numbers x, which are less than or equal to 120, are the solutions of the given inequality.
Hence, the solution set of the given inequality is (-∞, 120]
Answered by Pragya Singh | 1 year agoSolve each of the following in equations and represent the solution set on the number line \( \dfrac{5x}{4}-\dfrac{4x-1}{3}>1,\) where x ϵ R.
Solve each of the following in equations and represent the solution set on the number line.\( \dfrac{5x-8}{3}\geq \dfrac{4x-7}{2}\), where x ϵ R.
Solve each of the following in equations and represent the solution set on the number line. 3 – 2x ≥ 4x – 9, where x ϵ R.
Solve each of the following in equations and represent the solution set on the number line. 3x – 4 > x + 6, where x ϵ R.
Solve each of the following in equations and represent the solution set on the number line. 5x + 2 < 17, where
(i) x ϵ Z,
(ii) x ϵ R.