Solve the given inequality for real x : 37 – (3x + 5) ≥ 9x – 8 (x – 3)

Asked by Pragya Singh | 1 year ago |  106

Solution :-

Given that, 37 – (3x + 5) ≥ 9x – 8 (x – 3)

On simplifying we get

= 37 – 3x – 5 ≥ 9x – 8x + 24

= 32 – 3x ≥ x + 24

On rearranging

= 32 – 24 ≥ x + 3x

= 8 ≥ 4x

= 2 ≥ x

All the real numbers of x which are less than or equal to 2 are the solutions of the given inequality

Hence, (-∞, 2] will be the solution for the given inequality

Answered by Abhisek | 1 year ago

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