1 Answer
Solution :-
\( \dfrac{x}{2}≥\dfrac{(5x-2)}{3}-\dfrac{(7x-3)}{5}\)
= \( \dfrac{x}{2}≥\dfrac{5(5x-2)-3(7x-3)}{15}\)
= \( \dfrac{x}{2}≥\dfrac{25x-10-21x+9}{15}\)
=\( \dfrac{x}{2}≥\dfrac{4x-1}{15}\)
= \(15x≥2(4x-1)\)
= \(15x≥8x-2\)
=\( 15x-8x≥8x-2-8x\)
= \( 7x≥-2\)
= \( x≥-\dfrac{2}{7}\)
The graphical representation of the solutions of the given inequality is as follows.
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