Find all pairs of consecutive odd positive integers both of which are smaller than 10 such that their sum is more than 11.

Asked by Pragya Singh | 1 year ago |  62

Solution :-

Let us assume x be the smaller of the two consecutive odd positive integers

Other integer is = x + 2

It is also given in the question that, both the integers are smaller than 10

x + 2 < 10

x < 8 … (i)

Also, it is given in the question that sum off two integers is more than 11

x + (x + 2) > 11

2x + 2 > 11

x > $$\dfrac{9}{2}$$

x > 4.5 … (ii)

Thus, from (i) and (ii) we have x is an odd integer and it can take values 5 and 7

Hence, possible pairs are (5, 7) and (7, 9)

Answered by Abhisek | 1 year ago

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