Let us assume x be the smaller of the two consecutive odd positive integers

Other integer is = x + 2

It is also given in the question that, both the integers are smaller than 10

x + 2 < 10

x < 8 … (i)

Also, it is given in the question that sum off two integers is more than 11

x + (x + 2) > 11

2x + 2 > 11

x > \( \dfrac{9}{2}\)

x > 4.5 … (ii)

Thus, from (i) and (ii) we have x is an odd integer and it can take values 5 and 7

Hence, possible pairs are (5, 7) and (7, 9)

Answered by Abhisek | 1 year agoSolve each of the following in equations and represent the solution set on the number line \( \dfrac{5x}{4}-\dfrac{4x-1}{3}>1,\) where x ϵ R.

Solve each of the following in equations and represent the solution set on the number line.\( \dfrac{5x-8}{3}\geq \dfrac{4x-7}{2}\), where x ϵ R.

Solve each of the following in equations and represent the solution set on the number line. 3 – 2x ≥ 4x – 9, where x ϵ R.

Solve each of the following in equations and represent the solution set on the number line. 3x – 4 > x + 6, where x ϵ R.

Solve each of the following in equations and represent the solution set on the number line. 5x + 2 < 17, where

**(i) **x ϵ Z,

**(ii)** x ϵ R.