The longest side of a triangle is 3 times the shortest side and the third side is 2 cm shorter than the longest side. If the perimeter of the triangle is at least 61 cm, find the minimum length of the shortest side.

Asked by Pragya Singh | 1 year ago |  67

##### Solution :-

Let us assume the length of the shortest side of the triangle be x cm

According to the question, length of the longest side = 3x cm

And, length of third side = (3x – 2) cm

As, the least perimeter of the triangle = 61 cm

Thus, x + 3x + (3x – 2) cm ≥ 61 cm

= 7x – 2 ≥ 61

= 7x ≥ 63

Now divide by 7 we get

$$\dfrac{7x}{7} ≥\dfrac{63}{7}$$

= x ≥ 9

Hence, the minimum length of the shortest side will be 9 cm

Answered by Abhisek | 1 year ago

### Related Questions

#### Solve each of the following in equations and represent the solution set on the number line

Solve each of the following in equations and represent the solution set on the number line $$\dfrac{5x}{4}-\dfrac{4x-1}{3}>1,$$ where x ϵ R.

#### Solve each of the following in equations and represent the solution set on the number line.

Solve each of the following in equations and represent the solution set on the number line.$$\dfrac{5x-8}{3}\geq \dfrac{4x-7}{2}$$, where x ϵ R.

#### Solve each of the following in equations and represent the solution set on the number line. 3 – 2x ≥ 4x – 9,

Solve each of the following in equations and represent the solution set on the number line. 3 – 2x ≥ 4x – 9, where x ϵ R.

#### Solve each of the following in equations and represent the solution set on the number line. 3x – 4 > x + 6

Solve each of the following in equations and represent the solution set on the number line. 3x – 4 > x + 6, where x ϵ R.