Let us assume the length of the shortest side of the triangle be x cm
According to the question, length of the longest side = 3x cm
And, length of third side = (3x – 2) cm
As, the least perimeter of the triangle = 61 cm
Thus, x + 3x + (3x – 2) cm ≥ 61 cm
= 7x – 2 ≥ 61
= 7x ≥ 63
Now divide by 7 we get
= \( \dfrac{7x}{7} ≥\dfrac{63}{7}\)
= x ≥ 9
Hence, the minimum length of the shortest side will be 9 cm
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