A person needs a lens of power -5.5 dioptres for correcting his distant vision. For correcting his near vision he needs a lens of power +1.5 dioptre. What is the focal length of the lens required for correcting

(i) distant vision, and

(ii) near vision?

Asked by Vishal kumar | 1 year ago |  171

##### Solution :-

The power (P) of a lens of focal length f is given by the relation

$$Power\,(P)=\frac{1}{f}$$

(i) Power of the lens (used for correcting distant vision) = -5.5 D

Focal length of the lens (f) =$$\frac{1}{p}$$

$$f=\frac{1}{-5.5}$$

$$f =-0.181 m$$

The focal length of the lens (for correcting distant vision) is - 0.181 m.

(ii) Power of the lens (used for correcting near vision) = +1.5 D

Focal length of the required lens (f) = $$\frac{1}{p}$$

$$f=\frac{1}{1.5}=+0.667 \,m$$

The focal length of the lens (for correcting near version) is 0.667 m.

Answered by Shivani Kumari | 1 year ago

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