Given x + y ≥ 4
Putting value of x = 0 and y = 0 in equation one by one, we get value of
y = 4 and x = 4
The points for the line are (0, 4) and (4, 0)
Checking for the origin (0, 0)
0 ≥ 4
This is not true,
So the origin would not lie in the solution area. The required region would be on the right of lines graph.
2x – y < 0
Putting value of x = 0 and y = 0 in equation one by one, we get value of
y= 0 and x = 0
Putting x = 1 we get y = 2
So the points for the given inequality are (0, 0) and (1, 2)
Now that the origin lies on the given equation we will check for (4, 0) point to check which side of the lines graph will be included in the solution.
8 < 0 which is not true, hence the required region would be on the left side of the line 2x-y < 0
The shaded region is the required solution of the inequalities.
Solve each of the following in equations and represent the solution set on the number line \( \dfrac{5x}{4}-\dfrac{4x-1}{3}>1,\) where x ϵ R.
Solve each of the following in equations and represent the solution set on the number line.\( \dfrac{5x-8}{3}\geq \dfrac{4x-7}{2}\), where x ϵ R.
Solve each of the following in equations and represent the solution set on the number line. 3 – 2x ≥ 4x – 9, where x ϵ R.
Solve each of the following in equations and represent the solution set on the number line. 3x – 4 > x + 6, where x ϵ R.
Solve each of the following in equations and represent the solution set on the number line. 5x + 2 < 17, where
(i) x ϵ Z,
(ii) x ϵ R.