The inequality given is,
= – 12 < 4 – \( \dfrac{3x}{-5}\) ≤ 2
= \( 12 -4 < \dfrac{-3x}{-5} ≤ 2-4\)
= \( -16< \dfrac{3x}{5} ≤ -2\)
= \(80x< 3x≤ -10\)
= \(\dfrac{-80}{3}< x≤ \dfrac{-10}{3}\)
Thus, the solution set for the given inequality is (\( \dfrac{-80}{3}\), \( \dfrac{-10}{3}\)]
Answered by Abhisek | 1 year agoSolve each of the following in equations and represent the solution set on the number line \( \dfrac{5x}{4}-\dfrac{4x-1}{3}>1,\) where x ϵ R.
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