The inequality given is,

= – 12 < 4 – \( \dfrac{3x}{-5}\) ≤ 2

= \( 12 -4 < \dfrac{-3x}{-5} ≤ 2-4\)

= \( -16< \dfrac{3x}{5} ≤ -2\)

= \(80x< 3x≤ -10\)

= \(\dfrac{-80}{3}< x≤ \dfrac{-10}{3}\)

Thus, the solution set for the given inequality is (\( \dfrac{-80}{3}\), \( \dfrac{-10}{3}\)]

Answered by Abhisek | 2 years agoSolve each of the following in equations and represent the solution set on the number line \( \dfrac{5x}{4}-\dfrac{4x-1}{3}>1,\) where x ϵ R.

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