The inequality given is,

\( 7 ≤ \dfrac{(3x+11)}{2}≤ 11\)

14 ≤ 3x + 11 ≤ 22

⇒ 14 – 11 ≤ 3x + 11 – 11 ≤ 22 – 11

⇒ 3 ≤ 3x ≤ 11

⇒ 1 ≤ x ≤ \( \dfrac{11}{3}\)

Hence, all real numbers x greater than or equal to -4 but less than or equal to 2 are solution of given equality.

x ∈ [1, \( \dfrac{11}{3}\)]

Answered by Abhisek | 1 year agoSolve each of the following in equations and represent the solution set on the number line \( \dfrac{5x}{4}-\dfrac{4x-1}{3}>1,\) where x ϵ R.

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