The inequality given is,
\( 7 ≤ \dfrac{(3x+11)}{2}≤ 11\)
14 ≤ 3x + 11 ≤ 22
⇒ 14 – 11 ≤ 3x + 11 – 11 ≤ 22 – 11
⇒ 3 ≤ 3x ≤ 11
⇒ 1 ≤ x ≤ \( \dfrac{11}{3}\)
Hence, all real numbers x greater than or equal to -4 but less than or equal to 2 are solution of given equality.
x ∈ [1, \( \dfrac{11}{3}\)]
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