According to the question,

The solution has to be kept between 68° F and 77° F

So, we get, 68° < F < 77°

Substituting,

(\( \dfrac{9}{5}\)) C + 32

\(68 < \dfrac{9}{5}C + 32< 77\)

\( 68-32 < \dfrac{9}{5}C + 32-32< 77-32\)

\( 36< \dfrac{9}{5}C < 45\)

\( 36\times \dfrac{5}{9}<\dfrac{9}{5}C\times \dfrac{5}{9} <45\times \dfrac{5}{9}\)

20 < C < 25

Hence, we get,

The range of temperature in degree Celsius is between 20° C to 25° C

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