According to the question,
The solution has to be kept between 68° F and 77° F
So, we get, 68° < F < 77°
Substituting,
(\( \dfrac{9}{5}\)) C + 32
\(68 < \dfrac{9}{5}C + 32< 77\)
\( 68-32 < \dfrac{9}{5}C + 32-32< 77-32\)
\( 36< \dfrac{9}{5}C < 45\)
\( 36\times \dfrac{5}{9}<\dfrac{9}{5}C\times \dfrac{5}{9} <45\times \dfrac{5}{9}\)
20 < C < 25
Hence, we get,
The range of temperature in degree Celsius is between 20° C to 25° C
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