From a committee of 8 persons, in how many ways can we choose a chairman and a vice chairman assuming one person cannot hold more than one position?

Asked by Pragya Singh | 1 year ago |  86

##### Solution :-

In a committee of 8 persons, a chairman and vice chairman are selected in such away that one person can hold only one position. Thus, ways of choosing a chairman and vice chairman is permutation of 8 objects taken 2 at a time Therefore, number of ways

$$^8P_2= \dfrac{8!}{(8-2)!}=\dfrac{8!}{6!}=\dfrac{8\times 7\times 6!}{6!}$$

= 56

Answered by Abhisek | 1 year ago

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