In how many ways can a team of 3 boys and 3 girls be selected from 5 boys and 4 girls?

Asked by Pragya Singh | 1 year ago |  80

##### Solution :-

Given 5 boys and 4 girls are in total

We can select 3 boys from 5 boys in 5C3 ways

Similarly, we can select 3 boys from 54 girls in 4C3 ways

Number of ways a team of 3 boys and 3 girls can be selected is 5C3 × 4C3

5C3 × 4C3 =

$$\dfrac{5!}{3!(5-3)!}\times \dfrac{4!}{3!(4-3)!}$$

$$=\dfrac{5!}{3!\times 2!}\times \dfrac{4!}{3!\times 1!}$$

5C3 × 4C3 = 10 × 4 = 40

Number of ways a team of 3 boys and 3 girls can be selected is 5C3 × 4C3 = 40 ways

Answered by Abhisek | 1 year ago

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