Given 5 boys and 4 girls are in total
We can select 3 boys from 5 boys in 5C3 ways
Similarly, we can select 3 boys from 54 girls in 4C3 ways
Number of ways a team of 3 boys and 3 girls can be selected is 5C3 × 4C3
= 5C3 × 4C3 =
\( \dfrac{5!}{3!(5-3)!}\times \dfrac{4!}{3!(4-3)!}\)
\( =\dfrac{5!}{3!\times 2!}\times \dfrac{4!}{3!\times 1!}\)
5C3 × 4C3 = 10 × 4 = 40
Number of ways a team of 3 boys and 3 girls can be selected is 5C3 × 4C3 = 40 ways
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