Determine the number of 5 card combinations out of a deck of 52 cards if there is exactly one ace in each combination.

Asked by Pragya Singh | 1 year ago |  74

1 Answer

Solution :-

Given a deck of 52 cards

There are 4 Ace cards in a deck of 52 cards.

According to question, we need to select 1 Ace card out the 4 Ace cards

Number of ways to select 1 Ace from 4 Ace cards is 4C1

More 4 cards are to be selected now from 48 cards (52 cards – 4 Ace cards)

Number of ways to select 4 cards from 48 cards is 48C4

\( \dfrac{4!}{1!(4-11)!}\times \dfrac{48!}{4!(48-4)!}=\dfrac{4!}{1!\times 3!}\times \dfrac{48!}{4!\times 44!}\)

\( \dfrac{4\times 3!}{1!\times 3!}\times \dfrac{48\times 47\times 46\times 45\times 44!}{4!\times 44!}\)

\( \dfrac{4}{1}\times \dfrac{4669920}{24}\)

\( 4\times 194580\)

= 778320.

Number of 5 card combinations out of a deck of 52 cards if there is exactly one ace in each combination 778320.

Answered by Abhisek | 1 year ago

Related Questions

How many words each of 3 vowels and 2 consonants can be formed from the letters of the word INVOLUTE?

Class 11 Maths Permutations and Combinations View Answer

Find the number of permutations of n distinct things taken r together, in which 3 particular things must occur together.

Class 11 Maths Permutations and Combinations View Answer

How many words, with or without meaning can be formed from the letters of the word ‘MONDAY’, assuming that no letter is repeated, if

(i) 4 letters are used at a time

(ii) all letters are used at a time

(iii) all letters are used but first letter is a vowel ?

Class 11 Maths Permutations and Combinations View Answer

There are 10 persons named P1, P2, P3 …, P10. Out of 10 persons, 5 persons are to be arranged in a line such that is each arrangement P1 must occur whereas P4 and P5 do not occur. Find the number of such possible arrangements.

Class 11 Maths Permutations and Combinations View Answer

How many different words, each containing 2 vowels and 3 consonants can be formed with 5 vowels and 17 consonants?

Class 11 Maths Permutations and Combinations View Answer