Given 9 courses are available and 2 specific courses are compulsory for every student
Here 2 courses are compulsory out of 9 courses, so a student need to select 5 – 2 = 3 courses
Number of ways in which 3 ways can be selected from 9 – 2(compulsory courses) = 7 are 7C3
7C3 = \( \dfrac{7!}{3!(7-3)!}\)
= \( \dfrac{7!}{3!\times 4!}\)
7C3 = \( \dfrac{7\times 6\times 5\times 4!}{3!\times 4!}\)
= \( \dfrac{210}{6}=35\)
Number of ways a student selects 5 courses from 9 courses where 2 specific courses are compulsory are: 35
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