In how many ways can a student choose a programme of 5 courses if 9 courses are available and 2 specific courses are compulsory for every student?

Asked by Pragya Singh | 1 year ago |  68

##### Solution :-

Given 9 courses are available and 2 specific courses are compulsory for every student

Here 2 courses are compulsory out of 9 courses, so a student need to select 5 – 2 = 3 courses

Number of ways in which 3 ways can be selected from 9 – 2(compulsory courses) = 7 are 7C3

7C3$$\dfrac{7!}{3!(7-3)!}$$

$$\dfrac{7!}{3!\times 4!}$$

7C3 = $$\dfrac{7\times 6\times 5\times 4!}{3!\times 4!}$$

$$\dfrac{210}{6}=35$$

Number of ways a student selects 5 courses from 9 courses where 2 specific courses are compulsory are: 35

Answered by Abhisek | 1 year ago

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