There are a total of 11 letters out of which A, I and N appears 2 times and other letters appear only once.
The words starting with A will be the words listed before the words starting with E.
Thus, words starting with letter A will have letter A fixed at its extreme left end.
And remaining 10 letters are rearranged all at a time. In the remaining 10 letters, there are 2 I’s and 2 N’s.
Number of words starting with A = \( \dfrac{10!}{2!2!}=907200\)
Therefore, required number of words is 907200.
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