If the different permutations of all the letter of the word EXAMINATION are listed as in a dictionary, how many words are there in this list before the first word starting with E?

Asked by Abhisek | 1 year ago |  86

##### Solution :-

There are a total of 11 letters out of which A, I and N appears 2 times and other letters appear only once.

The words starting with A will be the words listed before the words starting with E.

Thus, words starting with letter A will have letter A fixed at its extreme left end.

And remaining 10 letters are rearranged all at a time. In the remaining 10 letters, there are 2 I’s and 2 N’s.

Number of words starting with A = $$\dfrac{10!}{2!2!}=907200$$

Therefore, required number of words is 907200.

Answered by Pragya Singh | 1 year ago

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