Write the general term in the expansion of (x2 – y x)12, x ≠ 0.

Question

Write the general term in the expansion of (x² – y x)¹², x ≠ 0.

Asked by Abhisek | 1 year ago | 103

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Accepted Answer

The general term T_r+1 in the binomial expansion is given by T_r+1 = ⁿC _r a^n-r b^r

Here n = 12, a= x² and b = -y x

Substituting the values we get

T_n+1 =¹²C_r × x^2(12-r) (-1)^r y^r x^r

= \( \dfrac{12!}{r!(12-r)!}\times x^{24-2r}-1^ry^rx^r\)

= \(-1^r \dfrac{12!}{r!(12-r)!}x^{24-r}y^r\)

= -1^{r 12}c_r.x^{24 –2r}. y^r

Answered by Pragya Singh | 1 year ago