Find an approximation of (0.99)5 using the first three terms of its expansion.

Asked by Pragya Singh | 1 year ago |  167

##### Solution :-

0.99 can be written as

0.99 = 1 – 0.01

Now by applying binomial theorem we get

(o. 99)5 = (1 – 0.01)5

5C(1)5 – 5C(1)4 (0.01) + 5C(1)3 (0.01)2

= 1 – 5 (0.01) + 10 (0.01)2

= 1 – 0.05 + 0.001

= 0.951

Answered by Abhisek | 1 year ago

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