Find the multiplicative inverse of the complex number 4 - 3i and evaluate

Asked by Abhisek | 1 year ago |  65

##### Solution :-

Let’s consider z = 4 – 3i

Then,

= 4 + 3i and

|z|2 = 42 + (-3)2 = 16 + 9 = 25

Thus, the multiplicative inverse of 4 – 3i is given by z-1

$$z^{-1}=\dfrac{\overline{z}}{|z|^2}=\dfrac{4+3i}{25}=\dfrac{4}{25}+\dfrac{3}{25}i$$

Answered by Pragya Singh | 1 year ago

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