Let’s consider \( z = \sqrt{5} + 3i\)
Then,
\( \overline{z}= \sqrt{5} -3i\) and
\( |z|^2=(\sqrt{5})^2+3^2=5+9=14\)
Thus, the multiplicative inverse of \(\sqrt{5} + 3i\) is given by z-1
z-1 = \( \dfrac{\overline{z}}{|z|^2}=\dfrac{ \sqrt{5} -3i}{14}\)
= \( \dfrac{ \sqrt{5}}{14}-\dfrac{3i}{14}\)
Answered by Abhisek | 1 year agoShow that 1 + i10 + i20 + i30 is a real number?
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